linux shell 条件基础判断 错误

发布网友 发布时间：2022-04-26 21:58

我来回答

共5个回答

热心网友 时间：2022-04-18 21:02

#!/bin.bash改成#!bin/bash,然后如下示:
#!/bin/bash

echo 'Please input number'
read number

if [ $number == 1 ];then
echo 'your number is 1'

elif [ $number == 2 ];then
echo 'your number is 2'

elif [ $number == 3 ];then
echo 'your number is 3'

else
echo 'your number is not'

fi

热心网友 时间：2022-04-18 22:20

#!/bin/sh

echo 'Please input number'
read number

if [ $number == 1 ];then
echo 'your number is 1'

elif [$number == 2 ];then
echo 'your number is 2'

elif [$number == 3 ];then
echo 'your number is 3'

else
echo 'your number is not'

fi

热心网友 时间：2022-04-18 23:54

如果用这个==比较，可以这样"$number" == "1"。

热心网友 时间：2022-04-19 01:46

判断的语句换成
${number} -eq "1"

热心网友 时间：2022-04-19 03:54

elif后面没有空格?