发布网友 发布时间:2024-10-22 08:27
共2个回答
热心网友 时间:2024-10-28 04:37
sin(2x-π/3)=根号3 /2
2x-π/3=2kπ+π/3或2x-π/3=2kπ+2π/3
x=kπ+π/3或x=kπ+π/2(k为整数)
cos3x<根号2/2
2kπ+π/4<3x<2kπ+7π/4
2kπ/3+π/12<3x<2kπ/3+7π/12(k为整数)
热心网友 时间:2024-10-28 04:37
1、sin(2x-π/3)=sqr(3) /2
2x-π/3=2kπ+π/3或2x-π/3=2kπ+π-π/3
x=kπ+π/3或x=kπ+π/2(k为整数)
2、由余弦函数图象可知道cos3x<sqr(2)/2
2kπ+π/4<3x<2kπ+7π/4
2kπ/3+π/12<x<2kπ/3+7π/12(k为整数)