发布网友 发布时间:2024-10-22 09:01
共1个回答
热心网友 时间:2024-11-06 13:05
设圆心A(a, 0), AC² = AD², (a + 1)² + (0 - 1)² = (a - 1)² + (0 - 3)², a = 2
AC² = r² = (2 + 1)² + (0 -1)² = 10
(x - 2)² + y² = 10
直线X+3y+7=0和3x-2y-12=0的交点A(2, -3)
r² = AC² = (-1 - 2)² + (1 + 3)² = 25
(x + 1)² + (y - 1)² = 25
2x - y = 3, y = 2x - 3
圆心C(c, 2c - 3)
AC² = BC², (c - 5)² + (2c - 3 - 2)² = (c - 3)² + (2c - 3 + 2)², c = 2
C(2, 1)
AC² = r² = (2 - 5)² + (1 -2)² = 10
(x - 2)² + (y - 1)² = 10